x^2+4x-108=0

Solution for x^2+4x-108=0 equation:

x^2+4x-108=0

a = 1; b = 4; c = -108;
Δ = b2-4ac
Δ = 42-4·1·(-108)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{7}}{2*1}=\frac{-4-8\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{7}}{2*1}=\frac{-4+8\sqrt{7}}{2}
$